First, you are going to distribute the 3 into the (6x+2x) and the 8 into the (5x+6). After that, the parenthesis should be gone. Then, move all the x values to one side, and the constants to the other. Then, solve as you normally would.
Answer:
A)3
Step-by-step explanation:
Method A: 7.6666.... = 7 + 0.6666... = 7 + 2/3 = 21/3 + 2/3 = 23/3
Method B: 10(7.666...) - 1(7.666...) = 76.666... - 7.666... = 69.000...
(10 - 1)(7.666...) = 69
7.666... = 69/9 = 23/3
Answer:
The answer is incorrect; the plus sign should be a minus sign (apex)
Step-by-step explanation:
Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as
where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
is the required r
