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Rudik [331]
3 years ago
15

List the integer values of n which satisfy the inequality 2 ​

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0

Answer:

2, 3, 4, 5, 6

Step-by-step explanation:

Hi there!

We're given that 2\le n < 7. This means that <em>n</em> can be any value in between 2 and 7, and also 2.

2

The integer values in between 2 and 7 are 3, 4, 5 and 6.

2, 3, 4, 5, 6

I hope this helps!

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Step-by-step explanation:

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If (x+k) 2 (x+2) = x² +14x²+60x+72<br> Find the value of k.<br><br> I will give brainliest
Wittaler [7]

George C.
Jul 24, 2018
(
x
+
2
)
(
x
+
6
)
2
=
0

Explanation:
Given:
x
3
+
14
x
2
+
60
x
+
72
=
0

By the rational roots theorem, any rational zeros of the given cubic are expressible in the form
p
q
for integers
p
,
q
with
p
a divisor of the constant term
72
and
q
a divisor of the coefficient
1
of the leading term.
That means that the only possible rational zeros are:
±
1
,
±
2
,
±
3
,
±
4
,
±
6
,
±
8
,
±
9
,
±
12
,
±
18
,
±
24
,
±
36
,
±
72
In addition, note that all of the coefficients are positive and the constant term is non-zero. As a result, any real zero (rational or otherwise) of this cubic must be negative.
So that leaves rational possibilities:
−
1
,
−
2
,
−
3
,
−
4
,
−
6
,
−
8
,
−
9
,
−
12
,
−
18
,
−
24
,
−
36
,
−
72
We find:
(
−
2
)
3
+
14
(
−
2
)
2
+
60
(
−
2
)
+
72
=
−
8
+
56
−
120
+
72
=
0
So
x
=
−
2
is a zero and
(
x
+
2
)
a factor:
x
3
+
14
x
2
+
60
+
72
=
(
x
+
2
)
(
x
2
+
12
x
+
36
)
Without trying any more of our "possible" zeros, we can recognise the remaining quadratic factor as a perfect square trinomial:
x
2
+
12
x
+
36
=
x
2
+
2
(
x
)
(
6
)
+
6
2
=
(
x
+
6
)
2
So the factored form of the given cubic equation can be written:
(
x
+
2
)
(
x
+
6
)
2
=
0

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3 years ago
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