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MrRa [10]
2 years ago
6

Can someone help with me with this. Thank you

Mathematics
1 answer:
Anastasy [175]2 years ago
6 0

your answer is going to be x 22 and y 34

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If log (m + n) = log m+log n, show that m =n/n-1​
Sedbober [7]

log (m + n) = log m+ log n and proved it m =n/n-1​

Given;

If log (m + n) = log m+ log n

To show that the m =n/n-1​

Now, According to the question:

We know that,

Log (m + n) = log m + log n

Log (m + n ) = log (mn).                 [log a + log b = log ab ]

Cancelling the log on both sides.

then,

m + n = mn

=> n = mn - m

=> n = m (n - 1)

=> m = n / n - 1

Hence Proved

log (m + n) = log m+ log n and proved it m =n/n-1​

What is Logarithm?

A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.

Learn more about Logarithm at:

brainly.com/question/16845433

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3 0
1 year ago
What is used to repair big brass band instruments
alina1380 [7]
<span> the answer tuba glue!

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5 0
3 years ago
Your answer must be simplified. x+5≤−4
PilotLPTM [1.2K]

Answer:

x≤−9

Step-by-step explanation:

x+5≤−4

-4-5=-9

you subtract 5 form each side

therefore x≤−9

hope this helps

4 0
3 years ago
Read 2 more answers
Determine whether or not the relation is a function. Please help asap
OLga [1]

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

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2 years ago
Heme d hey the girl who helped me please hl
mestny [16]

Answer:

Parallel segments → 1

perpendicular segments → 2

congruent segments → 3

---------

hope it helps...

have a great day!!

5 0
2 years ago
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