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Temka [501]
3 years ago
9

Find the difference quotient off, that is, find fly+h)-f(x) h h#0, for the following function. Be sure to simplify. f(x) = x^2 -

7x + 8 f(x+h)-f(x) h​
Mathematics
1 answer:
Sloan [31]3 years ago
3 0

The difference quotient for the function f(x) is h+2x-7

Given :

Difference quotient formula

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}

Given function f(x) = x^2 - 7x + 8

find the difference quotient using the formula

first we find out f(x+h) using given f(x)

replace x with x+h

f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8

Now replace it in our formula and also replace f(x)

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}\\ \frac{x^2+2xh+h^2-7x-7h+8-(x^2 - 7x + 8)}{h} \\\frac{x^2+2xh+h^2-7x-7h+8-x^2 + 7x - 8}{h} \\\\\frac{h^2+2xh-7h}{h}\\factor \; out \; h\\\frac{h\left(h+2x-7\right)}{h}\\h+2x-7

Learn more :brainly.com/question/23630564

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Answer:

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3 years ago
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3 years ago
Select the correct answer.
adelina 88 [10]

Answer:

c.

\frac{5}{4} x - 2 = \frac{3}{2} x-4

Step-by-step explanation:

a.

\frac{5}{2} x +\frac{7}{2} =\frac{3}{4} x+14 \\\frac{5}{2}x -\frac{3}{4} x=14-\frac{7}{2} \\\frac{10-3}{4} x =\frac{28-7}{2} \\\frac{7}{4} x =\frac{21}{2} \\x = \frac{21}{2} * \frac{4}{7} = 6 \\

b.

\frac{5}{4} x -9 = \frac{3}{2} x-12 \\\frac{5}{4} x - \frac{3}{2} x= -12 + 9 \\\frac{5-6}{4} x = -3 \\\frac{-1}{4} x = -3 \\x = -3 * -4 \\x = 12

c.

\frac{5}{4} x-2=\frac{3}{2} x-4 \\\frac{5}{4} x-\frac{3}{2} x=-4+2 \\\frac{5-6}{4}x=-2 \\\frac{-1}{4} x = -2 \\x = -2 * -4 \\x = 8

d.

\frac{5}{2} x -7 = \frac{3}{4} x+14 \\\frac{5}{2}x -\frac{3}{4} x=14+7 \\\frac{10-3}{4} x =21 \\\frac{7}{4} x =21 \\x = 21 * \frac{4}{7} = 12 \\

You could also replace x for 8 in every equation and see if both sides give the same answer

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Answer:

<u>$4,680</u>

Step-by-step explanation:

<u>Rate</u> : 10 dollars a week

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