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Alenkasestr [34]
2 years ago
14

A company is allowed to interview candidates until two qualified candidates are found. But budget constraints dictate that no mo

re than 10 candidates can be interviewed. List the sample space.
Mathematics
1 answer:
Lapatulllka [165]2 years ago
4 0

Answer:

Kindly check attached picture for sample space design

45 ways

Step-by-step explanation:

Number of qualified candidates to be chosen = 2

Number of candidates to be interviewed = 10

Combination formula :

nCr = n! / (n-r)! r!

10C2 = 10! ÷ (10 - 2)!2!

10C2 = 10*9 / 2 * 1

10C2 = 90/2

10C2 = 45 different samples

Our sample space will contain 45 different samples

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A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle
hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

5 0
2 years ago
Evaluate 2 sin 60° + tan 45° + cos²60°​
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1.25+√3 or 2.9821 to the nearest ten thousandth.

Step-by-step explanation:

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= √3 +  1.25

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3 years ago
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SVEN [57.7K]

Answer:

It's Tan.

Multiple Thumbs-up ^_^

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