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zepelin [54]
3 years ago
7

The question is below thanks

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0

this is ur complete Venn diagram

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inna [77]
An investment plan that guarantees payments at regular intervals after retirement

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4 years ago
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Use words to write a comparison statement for the problem above.
pantera1 [17]

Looking at the question we can see that it says:

41253>35214

We should know what these symbols mean:

stands for something less than the other, for example:

We can say that 2 is less than 5 so in a symbolic form it can be written as,

2

Similarly,

> stands for something greater than the other, for example:

We can say that 7 is greater than 5, in a symbolic form it can be written as,

7>5

So here, 42153>35214 means that, 42153 is greater than 35214.

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3 years ago
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WORTH 98 POINTS
LUCKY_DIMON [66]

Answer:

The equation is -3x^2 + 30x + 225 = 0, and the number of days is 15.

Step-by-step explanation:

I assume an x is missing, and the function is h(x) = -3x^2 + 30x + 225

You want to know the number of days in which the function value is zero.

-3x^2 + 30x + 225 = 0

Divide both sides by -3.

x^2 - 10x - 75 = 0

(x - 15)(x + 5) = 0

x - 15 = 0 or x + 5 = 0

x = 15 or x = -5

We discard the negative solution.

Answer: The equation is -3x^2 + 30x + 225 = 0, and the number of days is 15.

5 0
4 years ago
Michael spent $18 at a local farmers’ market. Apples cost $2 each and peppers cost $3 each.
boyakko [2]
2a+3p=18 because you don’t know how many apples or peppers you bought, all you know is how much money in total you spent which is $18
4 0
3 years ago
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We often deal with weighted​ means, in which different data values carry different weights in the calculation of the mean. For​
Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

A = 82.5*0.3 + 88.6*0.3 + 0.4x

A \geq 93.5

82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5

0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)

x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}

x \geq 105.425

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0
3 years ago
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