First box is 100 second is 4 third is 1500 4th box is 60 and last box is 1560
Answer:
I believe the answers are
B) 1
D) $1,000
Step-by-step explanation:
Answer:
The estimate of a population proportion is approximately 541.
Step-by-step explanation:
We can solve the the problem by using the formula for minimum sample needed for interval estimate of a population proportion which is given by the formula
n = pq ((Z/2) / E)^2
As, p is not defined so we use the standard p and q which is 0.5 and 0.5.
The reason for this is we have to choose form 0.1 to 0.9 both values of p and q, we will find the maximum value of pq occurs when they both are 0.5.
Next, we will find the value of (Z/2) by looking at the Z-table, we will find that at 98% confidence (Z/2) = 2.326. Now we start substituting the values in the above formula
n = (0.5)×(0.5) × (2.326/0.05)^2
n = 541.027
n ≅ 541.
Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F
Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.
Answer:
a) 
b) 
c), Yes;
Step-by-step explanation:
Michael's Weight: 
Al's weight: 
a) Ratio of Michael's weight to Al's weight: 
b) This ratio simplifies to: 

c) Yes, If the exponent in each expression were negative, then we have:
Ratio of Michael's weight to Al's weight: 
This ratio simplifies to: 
The two ratios are not the same.