We want to find
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Y = -0.4x
1) It is a straight line
2) I passes through the origin (0,0), because the y-intercpet is 0.
3) The slope is negative, so it passes throuh II and III quadrants
4) The magnitude of the slope = 0.4
4) The angle of the line with the negative side of the x-axis is that whose tan is 0.4 => angle = 21.8 °
With all that information you can identify the graph, given that you didn't include the options.
Answer:
6\sqrt[4]{x^3}[/tex]
Step-by-step explanation:
6x^3/4
is the same as
6 (x^3/4)
and the rule to change an exponent to a radical is power over root
so in this case, the power, 3 is over the root, 4
So it would be 6\sqrt[4]{x^3}[/tex]
63 in 4.5 hours
63 divided by 4.5 is 14 so
14 MPH would be your answer
