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stich3 [128]
3 years ago
13

What is .8 as a fraction and decimal?

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
7 0
.8 as a decimal is still .8 but as a fraction idk
s2008m [1.1K]3 years ago
6 0
0.8 as a fraction =  8/10  = 4/5          Divide top and bottom by 2

= 0.8 is already as a decimal.
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Sum of two positive number is always
Dafna1 [17]
The dune of two positive numbers is always positive. I hope this helps
3 0
3 years ago
Plz help ASAP !! will mark u brainlist
kogti [31]

Answer:

D. The 4th choice.

Step-by-step explanation:

We can see from the graph that the point (-2, -5) is excluded from the line since there is there an open circle.

The domain is all real numbers except -2.

The range is all real numbers except -5.

3 0
4 years ago
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Anyone know how to do this ????
SOVA2 [1]

There you go. Hope this helps.

5 0
3 years ago
The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
Butoxors [25]

Answer:

The value of x lies between 20 and 40 and value of y lies between -20 and 10

Step-by-step explanation:

We are given that

y\leq 40-x....(1)

y\leq x-20...(2)

First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.

Therefore, we can write as

y=-x+40...(3)

y=x-20...(4)

Adding equation (3) and (4) we get

2y=20

y=10

Substitute y=10 in equation (3) we get

10=40-x

x=40-10=30

(30,10) is the intersect point of two equation.

Put x=0 in equation (3)

y=40

Substitute y=0 in equation (3)

x=40

Substitute x=0 in equation (4)

y=-20

Substitute y=0 in equation (4)

x=20

Substitute x=0 and y=40 and in equation (1)

40\leq 40

Hence, the equation is true.Therefore, the shaded region below the line.

Substitute x=0 and y=-20 in equation (2)

-20\leq -20

The equation is true. Hence, the shaded region is below the line.

Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.

5 0
3 years ago
Read 2 more answers
Wish someone can do this for me.
Makovka662 [10]

Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .

To Find : To write those two inequality as a compound inequality with integers .

Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;

⇒ v + 8 ≤ -4 .

⇒ v ≤ -4 - 8.

⇒ v ≤ -12 .

Now , on simplifying the second inequality ,

⇒ v - 6 ≥ 10 .

⇒ v ≥ 10 + 6.

⇒ v ≥ 16 .

Hence the required answer will be :

\Large{\boxed{\red{\bf \blue{\dag} v\leqslant -12 \:\:or\:\:v\geqslant 16}}}

First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .

5 0
3 years ago
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