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3 years ago

Please find out what y=mx+c picture is attached above pls help!

Mathematics

1 answer:

mel-nik [20]3 years ago

3 0

First of all, your sample equation is wrong, it is y=mx+b, not y=mx+c, but anyway, the finished equation is going to be y=3, hope this helps

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Alina [70]

3 centimetres = 1 yard

Answer 1:

30 cm

Answer 2:

45 cm

Answer 3:

24 cm

Answer 4:

12 cm

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3 years ago

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aivan3 [116]

Answer:

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Step-by-step explanation:

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3 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

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4 years ago

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Ymorist [56]

It's the second one.

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3 years ago

Read 2 more answers

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umka2103 [35]

If w= (-p,-r,q) then answer would be (0,r)

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3 years ago