Answer:
(3x-4)(x-5)
Step-by-step explanation:
This is in the form
ax²+bx+c.
To factor this, we find factors of a·c that sum to b; this means factors of 3(20) = 60 that sum to -19:
60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10). The only of these that sum to -19 are -4 and -15. This means we will split up -19x into -4x and -15x:
3x²-4x-15x+20
Next we group the first two terms and the last two terms:
(3x²-4x)+(-15x+20)
Factor out the GCF of each group. For the first group, this is x:
x(3x-4)
For the second group, this is -5:
-5(3x-4)
The common factor for these two groups is (3x-4):
(3x-4)(x-5)
If its a parent then the answer would be 60
Answer:
25 is the correct answer because the amount of white socks out all of the socks is 2/8 which is equal to 1/4. 1/4 is 25%.
Answer:
The factorization of
is 
Step-by-step explanation:
This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form
or
. It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
Let's solve the factorization of
by using the <em>sum and difference of cubes </em>factorization.
1.) We calculate the cubic root of each term in the equation
, and the exponent of the letter x is divided by 3.
![\sqrt[3]{729x^{15}} =9x^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729x%5E%7B15%7D%7D%20%3D9x%5E%7B5%7D)
then ![\sqrt[3]{10^{3}} =10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E%7B3%7D%7D%20%3D10)
So, we got that
which has the form of
which means is a <em>sum of cubes.</em>
<em>Sum of cubes</em>

with
y 
2.) Solving the sum of cubes.


.
Answer:
The correct option is;
b. Stem and leaf plot
Step-by-step explanation:
A stem-and-leaf plot shows the data shape and the densities of the different classes in a graphical form such that the information in the data such as the data characteristics are self displayed by the data numbers arranged in the stem-and-leaf plot. The stem-and-leaf plot keeps the raw numerical data, in the form they were obtained and by their arrangement, outliers are easily spotted.