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Rashid [163]
2 years ago
11

How do you calculate the lenght of a triangle with a hypotenuse?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
5 0

Step-by-step explanation:

<em>Triangles and the Pythagorean Theorem</em>

  • The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2, can be used to find the length of any side of a right triangle.
  • The side opposite the right angle is called the hypotenuse (side c in the figure).

<em>(note: Pythagorean means hypotenuse)</em>

<em />

<em />

<em>hope this helps </em>

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Using the <u>normal distribution and the central limit theorem</u>, it is found that there is an approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

Normal Probability Distribution

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for n instances of a normal variable, the mean is n\mu while the standard deviation is s = \sigma\sqrt{n}.

In this problem:

  • Mean of 4 candies, hence \mu = 4.
  • Standard deviation of 1.5 candies, hence \sigma = 1.5.
  • She visited 35 houses, hence n = 35, \mu = 35(4) = 140, s = 1.5\sqrt{4} = 3

The probability is the <u>p-value of Z when X = 122</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{122 - 140}{3}

Z = -6

Z = -6 has a p-value of 0.

Approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

A similar problem is given at brainly.com/question/24663213

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Max wrote the number 0.785. After multiplying his number by a power of 10, he arrived at the number 7,850.0. What power of 10 di
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Step-by-step explanation:

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En un aeropuerto dos aviones A1 y A1 se acercan para aterrizar, si la ecuación de la trayectoria del primero es -x+2y-100=0, mie
liraira [26]

No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.

-------------------------

La trayectoria del primero es:

-x + 2y - 100 = 0

x_1 = 2y - 100

Para el segundo, tiene-se que:

-x + 200 + 2y = 0

x_2 = 2y + 200

Igualando los valores de x:

x_1 = x_2

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No hay solución en la que ambas trayectorias estén en la misma posición, puesto que no existe el riesgo de que sufran un choque entre ellos.

Un problema similar es dado en brainly.com/question/24653364

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