How do I factor this polynomial? q^2-121

Mathematics

1 answer:

Tresset [83]3 years ago

5 0

$q^2-121 =q^2-11^2=(q-11)(q+11)\\ \\ \\a^2-b^2 =(a-b)(a+b)$

You might be interested in

Evaluate the following expression

lina2011 [118]

Answer:

Hope this is correct

Step-by-step explanation:

HAVE A GOOD DAY!

6 0

3 years ago

-5 3/4 + -4 5/8 as a fraction

ruslelena [56]

Answer:

-10 3/8 or - 83/8

8 0

4 years ago

You buy a package of 12 pencils for $2.64 write this rate as a unit rate?

iogann1982 [59]

Unit rate means how much does it cost for 1 unit

2.64 for 12 pencils
find 1 pencil
divide both sides by 12
0.22 for 1 pencil

0.22 per pencil

3 0

3 years ago

Diego has 3 times as many comic books as Han.

Sloan [31]

Answer:

Han has 9 books

Step-by-step explanation:

If diego has 27 comic books than that means that all you have to do is divide 27/3. then that equals to 9

5 0

3 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0

3 years ago