This question is incomplete, the complete question is;
Assume that two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Which distribution is used to test the claim that women have a higher mean resting heart rate than men?
A.t
B.F
C.Normal
D. Chi-square
Answer:
A) t test
Step-by-step explanation:
A t-test uses sample information to assess how plausible it is for the population means μ1 and μ2 to be equal.
The formula for a t-statistic for two population means (with two independent samples), with unknown population variances shows us how to calculate t-test with mean and standard deviation and it depends on the assumption of having an equal variance or not.
If the variances are assumed to be not equal,
he formula is:
t = (bar X₁ - bar X₂) / √( s₁²/n₁ + s₂²/n₂ )
If the variances are assumed to be equal, the formula is:
t = (bar X₁ - bar X₂) / √ (((n₁ - 1)s₁² + (n₂ - 1)s₂²) / (n₁ + n₂ - 2)) ( 1/n₁ + 1/n₂)
it called t-test for independent samples because the samples are not related to each other, in a way that the outcomes from one sample are unrelated from the other sample.
hence option A is correct. t test
The value of the probability P(E and F) is 0.2802
<h3>Independent probability</h3>
Events are known to be independent if the occurrence of one does not affect the other.
Given the following parameters
P (E) =0.471
P(F) = 0.595
If E and F are independent, then;
P(E and F) = P(E)P(F)
P(E and F) = 0.471 * 0.595
P(E and F) = 0.2802
Hence the value of the probability P(E and F) is 0.2802
Learn more on independent events here: brainly.com/question/1374659
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Answer:
24X58-9=1,383
800x24=19,200
Step-by-step explanation:
24x58=(24x8)+(24x50)
24x8=160+32=192
24x50=200+1,000=1,200
192+1,200=1,392-9=1,383
800x24=3,200+16,000=19,200
It has to be at lest 9u2-4?
Just set it equal to zero and solve using the quadratic equation.
