3s(s-8)=0
3s = 0 s-8 =0
s=0 s= 8
First, you need to use the points to come up with a m (slope). To do this you must use the equation m= y2-y1/x2-x1. label the x in one pair of coordinates x1 and the y, y1. Then label the other x in the other pair of coordinates x2 and the y, y2. use the equation and figure the slope. Next, put the easiest coordinates into point-slope form. The equation you are to use is... y-y1=m(x-x1). Input the values and then distribute the m inside the parenthesis. Then you should be able to do the rest. The final product should be in slope-intercept form.
Answer:
Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.
This means that the value of k will go from 0 to 4, then all the numbers in the sum are:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
So we have 5 terms in our series.
b) to see the sign in each term, we must solve the powers, remember that:
(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
= 1 -1/2 + 1/4 - 1/8 + 1/16.
So the sign in each term of the series alternates.
Answer:
(-1,-1) and (4.1).
1+1
slope of the line: m= ------- = 2/5
4+1
the slope of the perpendicular line: -5/2 and point (-1,3)
(y-3) = -5/2(x+1)
Z=118 as vertically opposite angles are the same
x= (8x-50)
