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frez [133]
3 years ago
15

Consider 6x2 + 6x + 1. Which term immediately tells you that this expression is NOT a perfect square trinomial? Justify your ans

wer.
Mathematics
2 answers:
Rainbow [258]3 years ago
6 0

Answer:

6x^2

Step-by-step explanation:

6 isn't a perfect square

oksian1 [2.3K]3 years ago
4 0

Answer:

Step-by-step explanation:

The 6x^2 because 6  is not a perfect square.

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ABCD is a quadrilateral work out CD
Paladinen [302]

In a quadrilateral ABCD, the measure of the length of the quadrilateral CD will be 25.98 cm.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The length of AD will be

tan θ = AB/AD

AD = 12/ tan 35

AD = 17.14 cm

Then the value of the BD will be given by the Pythagoras.

BD² = AB² + AD²

BD² = 12² + 17.14²

BD² = 144 + 239.78

BD² = 437.78

BD = 20.92 cm

Then operate the sine rule in triangle BCD, we have

\dfrac{BD}{\sin C} = \dfrac{CD }{\sin B}\\\\\\\dfrac{20.92}{\sin 52} = \dfrac{CD }{\sin 102}\\\\\\CD = \dfrac{20.92 \times \sin 102}{\sin 52}

On further solving, the value of CD will be

CD = 25.98

More about the trigonometry link is given below.

brainly.com/question/22698523

#SPJ1

7 0
1 year ago
Help my little brother I don’t feel like helping him
garik1379 [7]
Wow that looks really easy.
4 0
2 years ago
3 8/20 in simplest form
daser333 [38]
It would be: 3 8/20 = 68/20 = 34/10 = 17/5

In short, Your Answer would be 17/5

Hope this helps!
7 0
3 years ago
Give an example of where you would use either the Commutative or Associative Property of Addition in a real world situation.
umka2103 [35]

So the best I could come up with is paper-rock-scissors; the operation takes two inputs and puts out the winner (assuming they are different).

So (paper rock) scissors= paper scissors = scissors,

But paper (rock scissors)= paper rock = paper.

This is a good example because it shows that associativity matters even outside of math.

3 0
3 years ago
Solve by using the quadratic formula: x^2 - 6x + 7 = 0 Please enter any square root values using "sqrt" or the decimal answer ro
olga nikolaevna [1]

Given parameters:

 Quadratic expression:

                 x² - 6x + 7 = 0

Solve using quadratic formula;

                      x   = \frac{-b +/- \sqrt{b^{2 } - 4ac} }{2a}

From the equation;

  a  = 1, b = -6 and c = 7

Input the parameters and solve;

           x = \frac{-(-6) +/- \sqrt{-6^{2 } + 4 x 1 x 7 } }{2 x 1}

          x = \frac{6 +/- \sqrt{36} +28 }{2}

        x = \frac{6 +/- \sqrt{64} }{2}

          x = \frac{6 + 8}{2 }    or \frac{6-8}{2}

          x = 7 or -1

         

6 0
3 years ago
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