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Ksivusya [100]
2 years ago
15

Please help quickly!! thanks!! :))

Mathematics
1 answer:
Svetlanka [38]2 years ago
3 0
ANSWER:D

Explained:
When in form y=mx+c , the c is the y intercept

Y^2=-x^2 +64
Y=-x + 8

For circle to cut x axis y must = 0
So Y=-x+8 becomes...
0=-x+8 |minus 8 from both sides
-8=-x
So x=8

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Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum
Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank  r (t) = 30 (1 - e^{-0.16 t} )

Initial volume of water in the tank = 800 gallons

The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

V_{total} = V_{i} + V_{pump}

V_{pump} = \int\limits^a_b {r(t)} \, dt

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

V_{pump} = \int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt

V_{pump} = 30 [ t + \frac{e^{-0.16t} }{0.16} ]

V_{pump} = 30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0}  )

V_{pump} = 420 gallon

Now, total volume in the tank

V_{total} = V_{i} + V_{pump}

V_{total} = 800 + 420

V_{total} = 1220 \ gallon

Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

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Independent variable: c

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