Given:
Number of red marbles = 8
Number of blue marbles = 5
Number of green marbles = 11
Number of yellow marbles = 1
One marble is selected at random.
To find:
The P(red, green or yellow).
Solution:
Number of red, green or yellow marbles = 8 + 11 + 1
= 20
Total number of marbles = 8 + 5 + 11 + 1
= 25
The probability of getting a red, green or yellow marble is:
![P(\text{red, green or yellow})=\dfrac{\text{number of red, green or yellow marbles}}{\text{Total number of marbles}}](https://tex.z-dn.net/?f=P%28%5Ctext%7Bred%2C%20green%20or%20yellow%7D%29%3D%5Cdfrac%7B%5Ctext%7Bnumber%20of%20red%2C%20green%20or%20yellow%20marbles%7D%7D%7B%5Ctext%7BTotal%20number%20of%20marbles%7D%7D)
![P(\text{red, green or yellow})=\dfrac{20}{25}](https://tex.z-dn.net/?f=P%28%5Ctext%7Bred%2C%20green%20or%20yellow%7D%29%3D%5Cdfrac%7B20%7D%7B25%7D)
![P(\text{red, green or yellow})=\dfrac{4}{5}](https://tex.z-dn.net/?f=P%28%5Ctext%7Bred%2C%20green%20or%20yellow%7D%29%3D%5Cdfrac%7B4%7D%7B5%7D)
![P(\text{red, green or yellow})=0.8](https://tex.z-dn.net/?f=P%28%5Ctext%7Bred%2C%20green%20or%20yellow%7D%29%3D0.8)
Therefore, the value of P(red, green or yellow) is 0.8.