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Tom [10]
3 years ago
11

The population of a community, p(x), is modeled by this exponential function, where x represents the number of years since the p

opulation started being,
recorded.
P(x) = 2,400(1.025)
What is the approximate population 3 years after the population started being recorded?
Mathematics
1 answer:
NeX [460]3 years ago
5 0

An exponential model is used to represent growth of a population

The population after 3 years is 2585

The function is given as:

\mathbf{P(x) = 2400(1.025)^x}

<em>3 years after</em>, means that x = 3

So, we have:

\mathbf{P(3) = 2400(1.025)^3}

Evaluate exponents

\mathbf{P(3) = 2400 \times 1.076890625}

\mathbf{P(3) = 2584.5375}

Approximate

\mathbf{P(3) = 2585}

Hence, the population after 3 years is 2585

Read more about population growth at:

brainly.com/question/3160736

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the area of a square is A = s^2, where s is the length of one side of the square. what is the side length s for each square ? th
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5 0
3 years ago
Write an equation of an ellipse in standard form with the center at the origin and a height of 12 units and width of 19 units.
gladu [14]

Answer:

The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

Step-by-step explanation:

* Lets revise the equation of the ellipse

- The standard form of the equation of an ellipse with center (0 , 0 )  

  and major axis parallel to the x-axis is x²/a² + y²/b² = 1  

# a > b  

- The length of the major axis is 2a  

- The coordinates of the vertices are ( ± a , 0 )  

- The length of the minor axis is 2b  

- The coordinates of the co-vertices are ( 0 , ± b )  

- The coordinates of the foci are ( ± c , 0 ) , where c ² = a ² − b²  

* Lets solve the problem

∵ The center of the ellipse is (0 ,0)

∵ Its width is 19 units

∴ The length of the major axis is = 19

∴ 2a = 19 ⇒ divide both sides by 2

∴ a = 19/2 ⇒ ∴ a² = 361/4

∵ Its height is 12 units

∴ The length of the minor axis is = 12

∴ 2b = 12 ⇒ divide both sides by 2

∴ b = 12/2 = 6 ⇒ ∴ b² = 36

- Lets write the equation in standard form

∵ The equation is x²/a² + y²/b² = 1

∴ x²/(361/4) + y²/36 = 1 ⇒ simplify it

∴ 4x²/361 + y²/36 = 1

* The equation of the ellipse in standard form is 4x²/361 + y²/36 = 1

7 0
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Let x = John's age now

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is equal to one third of what it will be in 5 years time: (1/3)(x+5)

 

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QveST [7]

Answer: What am I solving for?

Step-by-step explanation: ?

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