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The expression can be simplified as:
k^3(k7/5)^-5
= k^(3+-5) * (7/5)^-5
(Collecting the powers of k at one side and the constants at other side)
= k^-2 * (5/7)^5
(Solving thr integer powers)
= k^-2 * (3125/16807)
Answer:
3*(5*x-7)-(15*x-21)=0
Step-by-step explanation:
3 • (5x - 7) - (15x - 21) = 0
Step 2 :
Equation at the end of step 2 :
0 = 0
Step 3 :
Equations which are always true :
Answer:
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Answer:X/3X=3
We move all terms to the left:
X/3X-(3)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
We multiply all the terms by the denominator
X-3*3X=0
Wy multiply elements
X-9X=0
We add all the numbers together, and all the variables
-8X=0
X=0/-8
X=0
Step-by-step explanation: