Answer:
P(A or B) = 1.16
Step-by-step explanation:
Given probability:
Probability of event A = P(A) = 0.46
Probability of event B = P(B) = 0.7
P(A and B) = 0.43
Find:
P(A or B)
Computation:
If A is an incident and B is a separate event, P(A or B) is the possibility of either A, B, or both events occurring.
P(A or B) = P(A) + P(B)
P(A or B) = 0.46 + 0.7
P(A or B) = 1.16
Answer:
not enough to figure out :/
Well put 34 units on the left vertically and 17 units on the bottom hoizontially... fill it up and count how many you have
<h3>
Answer: 625</h3>
Work Shown:
The set {A,B,C,1,2} has five items. There are four slots to fill.
So we have 5^4 = 5*5*5*5 = 625 different possible passwords where the characters can be repeated.
