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2 years ago

Which rule best represents the

Mathematics

1 answer:

Gala2k [10]2 years ago

3 0

Answer:

Ig C im not sure tho

Step-by-step explanation:

Which rule best represents the

transformation graphed below?

A. (x,y) → (-x, y)

B. (x,y) → (-y, x)

C. (x, y) → (-x, -y)

D. (x,y) → (y, -x)

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What is the exponent in the power of 10?

Arisa [49]

X^10 the exponent would be 10

4 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

$\dfrac{A}{A'}=\dfrac{P^2}{P'^2}$

We are given:

A=72 dm^2 , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. $\dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}$

on taking square root on both the side we get:

$\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'$

Now putting the value of P in equation (1) we obtain:

$\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272$

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0

3 years ago

The month of July has 31 days. What is the greatest

Klio2033 [76]

4 is the most
in the month

3 0

3 years ago

The answer is x=25 y=20 But the answer i did was x=35 y=10 please help me solve this question I dont know if i am correct or the

Julli [10]

The two equations should be x+y=45 and 1.2x+y=52. Plug in x=35 y=10 into the second equation... then plug in x=25 and y=20 in the second equation

8 0

3 years ago