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3 years ago

15

In one school day activity, ¾ of 24 girls wore a mini skirt for their presentation. How many girls wore mini skirt? (Use AGONSA.

)

2 answers:

yKpoI14uk [10]3 years ago

6 0

Answer:

18

Step-by-step explanation24/0.75 is 18

mezya [45]3 years ago

3 0

Answer:

18

Explanation:

Not sure what you mean by AGONSA but the method to get 18 is;

$\frac{24}{1} *\frac{3}{4} = \frac{72}{4} = 18$

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Answer asap plz

babunello [35]

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Therefore, the <span>graphical representation that would best display the number of points a home team and a visitor’s team scored in each game this season is the double bar graph.</span>

3 0

3 years ago

Which multiplication expression is eqeul to 3/5 ÷ 1/2

eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

$1 \frac{1}{5}$

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

$1 \frac{1}{5}$

So option a = 3/5 x 2/1 is ur answer

8 0

2 years ago

Read 2 more answers

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

L( y′+3 y) = L(9 t)

<em>Using Formula Transform of derivatives</em>

<em> L(y¹(t)) = s y⁻(s)-y(0)</em>

<em> By using Laplace transform formula</em>

<em> </em> $L(t) = \frac{1}{S^{2} }$ <em> </em>

<em>Step(ii):-</em>

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

<em> B = 9/3 = 3</em>

Put s = -3 in equation(i)

9 = C(-3)²

<em>C = 1</em>

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

<em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

<u><em>Step(iv):-</em></u>

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

<em>By using inverse Laplace transform</em>

<em></em> $L^{-1} (\frac{1}{s} ) =1$ <em></em>

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

HELPPPP MEE !!!!!!!!!!!!!

ale4655 [162]

Answer:

સંગઠનોમાં અસરકારક ટીમો: તેમની પોતાની દિશા નિર્ધારિત કરો, મેનેજરો પસંદ કરેલા લોકોને માધ્યમ નક્કી કરે છે અને તેમને તાલીમની જરૂર હોતી નથી કારણ કે સભ્યો અસરકારક રીતે કાર્ય કરવા માટે તેમની પોતાની જરૂરિયાત ઓછી અથવા કોઈ માળખું વિકસાવે છે, કોચિંગ, પરામર્શ અને ચોક્કસ સપોર્ટની જરૂર છે. તેમની કામગીરી દરમિયાન અંતરાલો.

5 0

3 years ago

Which story problems could be solved using the given equation? 15÷10=? Choose exactly two answers that are correct. Brandy bough

Tatiana [17]

Multiply by the reciprocal by 3 and divide the common denominator by 14

3 0

3 years ago