def is_list_even(my_list):
for i in my_list:
if(i%2 != 0):
return False
return True
def is_list_odd(my_list):
for i in my_list:
if(i%2 == 0):
return False
return True
def main():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
if(is_list_even(lst)):
print('all even')
elif(is_list_odd(lst)):
print('all odd')
else:
print('not even or odd')
if __name__ == '__main__':
main()
Answer: Escape
Explanation: Exiting/Escaping current state within navigation is the universally needed action. Navigation menus can be complex and are hierarchical in nature. Users make mistakes and the only remedy is an escape function.
Answer:
For many years, opponents of multiple inheritance have argued that it adds complexity and ambiguity to situations like the "diamond dilemma," in which it's unclear which parent class a certain feature is inherited from if more than one parent class implements the same feature.
Explanation: