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2 years ago

Solve for the variable rin this equation: a(c+b)=d

Mathematics

1 answer:

strojnjashka [21]2 years ago

5 0

Answer:

The answer is option A c=d-ab\a

Step-by-step explanation:

Solution,

here

a(c+b) =d

or, ac+ab=d

or, ac=d-ab

.:c=d-ab/a

hope it helps

good day ❤️✅

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Help me with these math questions.

Olegator [25]

graph A

no x-intercept

no y-intercept

H.A is y = 5

V. A. is x = 0

*****************************************

Answer: $\frac{150}{31}$

<u>Step by step explanation:</u>

log₆(5x + 6) - log₆(x - 4) = 2

log₆ $(\frac{5x+6}{x-4})$ = 2

$(\frac{5x+6}{x-4})$ = 6²

$(\frac{5x+6}{x-4})$ = 36

5x + 6 = 36(x - 4)

5x + 6 = 36x - 144

6 = 31x - 144

150 = 31x

$\frac{150}{31}$ = x

**********************************************************

Answers:

a. (-1, -5)
b. up
c. x = -1
d. $\frac{-2+\sqrt{15}}{3} and\frac{-2-\sqrt{15}}{3}$
e. -2
f. see attachment
g. domain (-∞, ∞) range [-5, ∞)

<u>Explanation:</u>

f(x) = 3x² + 6x - 2

a=3 b=6 c=-2

x = $\frac{-b}{2a} =\frac{-6}{2(3)} = \frac{-6}{6} = -1$

Axis Of Symmetry: x = -1

f(-1) = 3(-1)² + 6(-1) - 2

= 3 - 6 - 2

= -5

Vertex: (-1, -5)

x = $\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

= $\frac{-6+/-\sqrt{6^{2}-4(3)(-2)}}{2(3)}$

= $\frac{-6+/-\sqrt{36+24}}{6}$

= $\frac{-6+/-\sqrt{60}}{6}$

= $\frac{-6+/-2\sqrt{15}}{6}$

= $\frac{-2+/-\sqrt{15}}{3}$

x-intercepts: $\frac{-2+/-\sqrt{15}}{3}$

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Answer:

-4

Step-by-step explanation:

Two legs of the triangle are congruent as shown by the tick marks. This means that this is an isosceles triangle; in an isosceles triangle, the two base angles are also congruent. Which means <A and <B are congruent.

So to solve for x, set 28 and 10x+68 equal to each other.

28=10x+68

First, subtract 68 from both sides

-40=10x

Then, divide both sides by 10

-4=x

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