I hope this helps you
g^2+14g+40
(g+4)(g+10)
g+4=9
g+10=15
We cannot agree with Danika. Why? Well, The reasoning is given as follows:
Two functions are inverses of each other if and only if it is true that the composition function is given by:
Everything is ok up to this point, right?. But let's prove that this is not fulfilled for these functions, then:
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As you can see we did not obtain the function that matches the definition of </span>inverse functions. For that reason <em>we can't agree with Danika</em>.
Answer:
STUV is a square
Step-by-step explanation:
segment length² = (x-x₁)² + (y-y₁)²
ST²: (-9 - 1)2 + (14 - 10)² = (-10)² + 4² = 116 (the rest follow this formula)
TU² = 116 TV² = 232 SU² = 232 SV² = 116 UV² = 116
ST = TU =SV = UV (4 sides congruent)
TV = SU (diagonal equal)
This is a square
Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)