Answer:
Frequency of allele A1- 0.41
Explanation:
In Hardy weinberg equilibrium,
P refers to the dominant allele
q refers to the recessive allele
The allele frequency will be p+q=1
The genotypic frequency is- P²+q²+2pq=1
P²= genotype of dominant trait ( A1A1)- 77
2pq= genotype of heterozygotes (2pq)- 65
q²= genotype of recessive trait (A2A2)- 123
Total number of offsprings= 77+ 65+ 123
= 265
Now to calculate allele frequency of A1=
= 77/265 + 1/2( 65//265)
= 0.290+ 0.122
= 0.413
Thus, 0.41 is correct.
<span>Within a protein, multiple amino acids are linked together by peptide bonds, thereby forming a long chain. Peptide bonds are formed by a biochemical reaction that extracts a water molecule as it joins the amino group of one amino acid to the carboxyl group of a neighboring amino acid. </span>
I know DNA and stuff is super hard to learn I had to look at my old notes.
It's called telophase in mitosis
Answer:
Troponin
Explanation:
This is a complex of three proteins (Trop C, I, T) that are responsible for muscle contraction of the skeletal and cardiac muscles . its binds with protein tropomysin to lie in the grove between the actin filaments. its prevents contraction by blocking myosin crossbridge in a relax muscles.Inorder to aid contractions calcium ions binds with troponin, which leads to confrontational change.This exposes myosin on actin filaments, leading to formation of crossbridge and therefore contraction of muscles.
Therefore if there is a mutation in the gene that encoded Troponin, as explained above, calcium ion will not be able to bind with tropinin, and there will be no exposure of myosin on actin filaments, no binding of myosin on actin to cause crossbridge, and consequently no muscle contraction,
Thus the intercoastal muscle and diaphragm will not contract leading to death of the baby.
Answer:
This is an incomplete question without the options.
Here are the options to pick from
DY
PLAY
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Within a six-base DNA recognition sequence, an enzyme that cuts between the 3rd and 4th bases from the 5' end will generate blunt ends.
a)True
b)False
a) True
What is the function of restriction endonucleases in bacteria?
a) They serve no function.
b)They allow bacteria to genetically recombine with other bacteria.
c) They allow bacteria to engineer new DNA fragments.
d)They provide a defense mechanism against infection by viruses.
Our answer is surely D
d)They provide a defense mechanism against infection by viruses.
Explanation:
Restriction enzyme/restriction endonuclease:
Are produced by bacteria for cleaveing DNA at specific sites. Restriction enzymes cleave foreign DNA in the bacterial cell to fight against infecting organisms.
Pls Note:
Restriction enzyme are used by
bacteria to defend against bacterial viruses called bacteriophages or phages
