Question

PLEASE HELP!! WILL BE GIVING BRAINLIEST TO THE CORRECT ANSWER!!!

Answer 1

Answer:

$E(x) = 99$

Step-by-step explanation:

Given

The attached table

Required

Number of times 3 or 4 will occur

First, we complete the table as follows:

$P(1) + P(2) +......+P(6) =1$

$0.13 + 0.05 + P(3) + 0.21 + 0.19 + 0.3 = 1$

Collect Like Terms

$P(3)= 1 -(0.13 + 0.05 + 0.21 + 0.19 + 0.3 )$

$P(3)= 0.12$

The expected number of times is:

$E(x)= n * P(x)$

So, we have:

$E(x) = 300 * (0.12 + 0.21)$

$E(x) = 300 * (0.33)$

$E(x) = 99$