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Mamont248 [21]
3 years ago
15

Suppose Albers Elementary School has 44 teachers and Bothel Elementary School has 74 teachers. If the total number of teachers a

t Albers and Bothel combined is 87, how many teachers teach at both schools?
Mathematics
2 answers:
sladkih [1.3K]3 years ago
6 0

Answer: 31

Step-by-step explanation:

This is solved Using the theory of sets.

Teachers in Albers school = 44

Teachers in Bothel school = 74

Let the number of teachers that work in both schools be denoted as "x"

This implies that:

Number of teachers in Albers only = 44 - x

Number of teachers in Bothel only = 74 - x

And total number of teachers in both schools = 87,

then

x + (44-x) + (74-x) = 87

118 -x = 87

31 = x

This means the number of teachers that teach in both schools = 31.

kap26 [50]3 years ago
6 0

Answer: I think I'm wrong but I believe its 205

Step-by-step explanation:

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Simplify the expression completely. 7b+3(4b−2)+6÷3
Karo-lina-s [1.5K]

Answer:

19b-4

Step-by-step explanation:

7b+3(4b-2)+6÷3

Bracket comes first so we distribute 3 over the terms in the bracket

= 7b + 12b -6 +6 ÷ 3

First we solve division

= 7b + 12b -6 +6 ÷ 3

= 7b + 12b -6 +2

= (7b+12b)+(-6+2)

= 19b -4

This can't be simplified further as it can't be solved anymore

4 0
3 years ago
Read 2 more answers
Evaluate and simplify the following complex fraction.:6/7 ÷ 3/11​
inna [77]

Answer:

3  7/50

Step-by-step explanation:

so you need them to become common denominators

a common multiple they both have would be is 77

6/7 becomes 66/77 and 3/11 becomes 21/77

now we divide

keep the 66/77 as is and flip 21/77 (keep, change, flip)

so now our equation looks like this: 66/77 x 77/21

and your answer is 3.14

but as a fraction it is 157/50 and to simplified it would be 3 7/50 (mixed fraction)

3 0
2 years ago
Sheeesh please help pls
Mariulka [41]
Area of a circle is:
A = (3.14)r^2

The picture shown is that the radius is 4

So,

A = (3.14)4^2

A = 50.2


~
6 0
3 years ago
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A bag contains 4 red and 6 green gumballs. if you select 5 of them without looking, how many ways can you get exactly 3 red or e
marusya05 [52]
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,

4C3 = 4!/3!(4 - 3)! = 4 ways

If you want to get 2 green out of the total 6, then that would be 6C2. That means,

6C2 = 6!/2!(6-2)! = 15 ways

Therefore, there are a total of 4+15 = <em>19 ways</em>.
8 0
3 years ago
Only answer if you know the correct answer! Thanks! :)
Komok [63]

Answer:

1. A

2. C

3. D

4. B

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3 years ago
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