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3 years ago

I need help with his Math question.

Mathematics

1 answer:

morpeh [17]3 years ago

5 0

Answer:

Part A-4.6 miles.

Part B-2.1

Step-by-step explanation:

1.7^2 + 4.3^2 = c

c=4.6

Part A) The length of a straight line between the school and the Fire Station is 4.6

Part B) The length of a straight line between the school and the hospital is 2.1

(Work for part B screenshot didnt save right so here's a link to a similar question that has similar work to mine :) )

brainly.com/question/15515217

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Andrea has a savings account with $80 that earns 2% interest per

lianna [129]

Answer:

After 10 years, she will has $96 in her bank.

Step-by-step explanation:

It is given that Andrea's saving account is $80 and earns 2% interest per year as a Simple Interest (Not Compounded). Using simple interest formula, Interest = (P×R×T)/100 where P is the principal, R is the interest rate and T is number of years :

$I = \frac{p \times r \times t}{100}$

P = $80

R = 2%

T = 10 years

$I = \frac{80 \times 2 \times 10}{100}$

$I = \frac{1600}{100}$

$I = 16$

It is given that the interest amount is $16. So the total amount she has after 10 years in the bank is $96 :

interest amount = $16

principal = $80

total = $16 + $80

= $96

8 0

3 years ago

What is 1.5 as a ratio

Kitty [74]

Answer: 3/2

Step-by-step explanation:

3 0

3 years ago

A rectangular painting by Leonardo da Vinci measured 62cm along its diagonal. If the painting has a height of 42 cm how wide is

IRINA_888 [86]

ANSWER

45.6cm to the nearest tenth.

EXPLANATION

The diagonal of the rectangular painting is 62cm.

The height of the painting is 42 cm.

The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.

From the Pythagoras Theorem,

${w}^{2} + {42}^{2} = {62}^{2}$

${w}^{2} = {62}^{2} - {42}^{2}$

${w}^{2} = 2080$

${w} = \sqrt{2080}$

$w = 4 \sqrt{130}$

The width of the painting is 45.6cm to the nearest tenth.

4 0

3 years ago

Could somebody please help me with this?

BARSIC [14]

For this problem, we are going to use the Remainder Theorem. This says that for $x - n$ to be a factor of a polynomial $p(x)$ , then $p(n) = 0$ . Essentially, it says that $x - n$ is a factor if when you substitute $n$ into the polynomial you get a result of 0.

Thus, in our case, when we substitute $x = 2$ into the polynomial, we should get an answer of 0 if $x - 2$ is a factor of the polynomial. Given this information, we can solve for $c$ :