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Montano1993 [528]
3 years ago
8

Explain how to use a net to find the surface area of a prism

Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0

Answer:

To find the total surface area of a prism, you need to calculate the area of two polygonal bases, i.e., the top face and bottom face. And then calculate the area of lateral faces connecting the bases. Add up the area of the two bases and the area of the lateral faces to get the total surface area of a prism.

Step-by-step explanation:

r-ruslan [8.4K]3 years ago
3 0

Answer:

use a net to fin surface area of a prism by multyplying 10 to the power of 50

Step-by-step explanation:

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Andre45 [30]

Answer:

1. 194

2. 189

Step-by-step explanation:

1. 991 - 797 = 194

2. 826 - 637 = 189

8 0
2 years ago
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Elodia [21]

We want to evaluate

\displaystyle \int_{-\frac1{\sqrt2}}^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx

First we note that the integrand is even (replacing x with -x doesn't fundamentally alter the function being integrated), so this is equal to

\displaystyle 2 \int_0^{\frac1{\sqrt2}} \sqrt{\left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2} \, dx

The radicand reduces significantly to

\displaystyle \left(\frac{x-1}{x+1}\right)^2 + \left(\frac{x+1}{x-1}\right)^2 - 2 = \frac{16x^2}{(1-x^2)^2}

so that taking the square root, we simplify the integral to

\displaystyle 8 \int_0^{\frac1{\sqrt2}} \frac x{1-x^2} \, dx

which is trivially computed with a substitution of y = 1 - x^2 and dy=-2x\,dx:

\displaystyle -4 \int_1^{\frac12} \frac{dy}y = 4 \int_{\frac12}^1 \frac{dy}y = -4 \ln\left(\frac12\right) = \ln(2^4) = \boxed{\ln(16)}

7 0
2 years ago
A rabbit and a turtle run 100 meters. When the rabbit finished, the turtle was behind by 80 meters. Next time they want to finis
d1i1m1o1n [39]

From the fraction solved, the distance that the rabbit should be behind the turtle will be 400 meters.

<h3>How to solve the distance</h3>

From the information, it was stated that a rabbit and a turtle run 100 meters and that when the rabbit finished, the turtle was behind by 80 meters. Therefore, the distance covered by the turtle will be:

= 100 - 80

= 20 meters

Therefore, the fraction of their distance will be:

= 20/100 = 1/5

Therefore, the number of meters behind the turtle that the rabbit should start will be:

= 80 × 5

= 400 meters.

Learn more about distance on:

brainly.com/question/2854969

3 0
2 years ago
Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for
makvit [3.9K]

Answer:

1035.75

Step-by-step explanation:

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What are matching partial products?
motikmotik
Just say partial products that relate to one another
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