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Aliun [14]
2 years ago
10

Need helpppppp pleaseeeeee help mememememee

Mathematics
1 answer:
LuckyWell [14K]2 years ago
8 0

Answer:

Step-by-step explanation:

v=3+1.5x7

v= 13.5 m/s

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Answer:

T= 1.29k

Step-by-step explanation:

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Find the 6th term term of the arithmetic sequence 8,5,2,-1
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2 years ago
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In rectangle WXYZ, A is on side WX such that AX = 4, B is on side YZ such that BY = 18, and C is on side XY such that angle ACB=
Lemur [1.5K]

Answer:2*sqrt(130)

Step-by-step explanation:From right triangle $AXC$, we have $\angle XAC = 90^\circ - \angle XCA$. We also must have $\angle YCB + \angle ACB + \angle XCA = 180^\circ$, so $\angle YCB = 180^\circ - 90^\circ - \angle XCA = 90^\circ - \angle XCA$, which means $\angle YCB = \angle XAC$. Combining this with $\angle X = \angle Y$, we have $\triangle XCA \sim \triangle YBC$ by AA Similarity, and\[\frac{CX}{AX} = \frac{BY}{CY},\]so\[\frac{CX}{4} = \frac{18}{2CX}.\]\\\\This gives us $2CX^2 = 72$, so $CX^2 =36$ and $CX=6$. \\\\\\\\Therefore, $CY = 12$.Applying the Pythagorean Theorem to right triangles $XCA$ and $CYB$ gives us\begin{align*}CA^2 &= XA^2 + XC^2 = 16 + 36 = 52,\\BC^2 &= CY^2 + BY^2 = 144 + 324 = 468.\end{align*}Applying the Pythagorean Theorem to right triangle $ABC$ gives\[AB = \sqrt{AC^2 + BC^2} = \sqrt{52 + 468} = \sqrt{520} = \boxed{2\sqrt{130}}.\](We can also compute $AB$ by dropping a perpendicular from $A$ to $\overline{YZ}$, which creates a right triangle.)

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3 years ago
I need the answer pls, answer fast I am I s choool
leva [86]

Answer:

Hello! answer: D. 180

Step-by-step explanation:

What you do for these is find the surface area for each face separately then add them up so...

for the sides its 18 for the top and bottom it's 48 for the front and back it's 24 so now we add all 6 up so... 18 + 18 + 48 + 48 + 24 + 24 = 180 Hope that helps!

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2 years ago
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