Answer:
Both of these daughter cells will then go on to divide once more in meiosis II, producing 4 daughter cells, 2 with n+1 and 2 with n-1. Nondisjunction in meiosis II results from the failure of the sister chromatids to separate during anaphase II.
Answer:
The correct answer will be- 200
Explanation:
The cell cycle in eukaryotes mostly takes place in four phases: G₁, S, G₂ and M phase in sequence.
The DNA replication takes place during S phase which doubles the amount of DNA in a cell after which during M- phase the DNA divides into the daughter cell.
The amount of DNA present during G₂ phase is the 200 pg which will remain same until anaphase I as the segregation of chromosomes to the daughter cells takes place in the anaphase. Therefore, the amount of DNA observed after G₂ phase will remain 200 pg till metaphase I.
Thus, 200 is the correct answer.
When cloning by restriction digest and ligation, you use restriction enzymes to cut open a plasmid (backbone) and insert a linear fragment of DNA (insert) that has been cut by compatible restriction enzymes. An enzyme, DNA ligase, then covalently binds the plasmid to the new fragment thereby generating a complete, circular plasmid that can be easily maintained in a variety of biological systems. Read on for an in-depth breakdown of how to do perform restriction digests.
A primary air pollutant is directly from the source and secondary pollutants are omitted from two or more different primary pollutants interact with each other in the atmosphere.
EX of primary: carbon monoxide, nitrogen oxide, sulfur oxid
EX of secondary: NO2 acid rain
No,they kill all ages for ex.A pack of lions went hunting leaving their cubs behind and a pack of hyenas come and they are hungry they will eat the food that they can
