The first two negatives cancel out and you're left with positive 4. Now go inside the square root and do the exponent. -4*-4 = 16. Then do the -4*3*1 = -12. Do 16-12 = 4. now the square root of 4 = 2. at the dominator is 2*3 = 6. right now they problem should look like 4+- 2/ 6. from there you split the problem in two. so you have 4+2/6 & 4-2/6 then you solve both problems.
6/6 2/6
1 1/3
1 & 1/3 are your answers. I hope this helped!
Can u add the dot plot? Then I can help you! :D
So I’m going to solve this using algebra OK?
So what you do is take the first integer as X.
Then we know that x(the first number) + X+2(the second number) is 288 right?
So we solve that saying x+x+2=288.
So 2X+2=288
2X+2-2=288-2 right?
So 2X=286.
So x is 286/2 right?
So x is 143.
Now the first number is 143 right?
So the second number should be 143+2 so 145.
I know they are not even but these are the solutions.
I don’t think there are any consecutive even numbers that add up to 288
Answer:
2/3
Step-by-step explanation:
Do 1/3 divided by 4/5 first.
So we are going to flip 4/5 to 5/4. The equation is now:
1/4+1/3 times 5/4
Now we are going to do the multiplication since multiply and division is before adding and subtraction.
1/3 times 5/4 = 5/12
Now we have to add 1/4+5/12
With adding ( and subtracting) we have to find the common denominator which is 12
So now we have 3/12 + 5/12 = 8/12 which reduces to 2/3
