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Maksim231197 [3]
3 years ago
13

What is 6 divided by 7 in fraction form?

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

Since 6 divided by 7 is already its simplest form, you would just right it like so.

6/7

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Determine the two positive integers each square root falls between.
sertanlavr [38]

Answer:

  10. (5, 6)

  11. (1, 2)

  12. (7, 8)

  13. (10, 11)

  14. (27, 28)

  15. (11, 12)

Step-by-step explanation:

If you're not familiar with the squares of small integers, your calculator can help you figure this.

10. √28 ≈ 5.291 . . . . between 5 and 6

11. √3 ≈ 1.732 . . . . between 1 and 2

12. √59 ≈ 7.681 . . . . between 7 and 8

13. √115 ≈ 10.724 . . . between 10 and 11

14. √772 ≈ 27.785 . . . . between 27 and 28

15. √140 ≈ 11.832 . . . . between 11 and 12

5 0
3 years ago
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nadya68 [22]

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3 0
3 years ago
Solve x2 + 10x = -21.
Arisa [49]
Answer is x = -7 and x = -3

<span> x2 + 10x = -21
</span><span> x2 + 10x + 21 = 0
</span>(x +3) (x +7) = 0

(x +3) = 0
and
(x + 7) = 0
so x = - 3 and x = -7
8 0
4 years ago
Adrian spent $19.35 on school supplies he bought two poster boards for $2.25 each he spent the remaining amount on notebooks tha
dusya [7]
9 because when you subtract the amount of poster money from the total ($19.35), you get $14.85. $14.85 divided by $1.65 is 9, which means he bought 9 notebooks.
4 0
3 years ago
The product of the least and greatest of three consecutive negative odd integers is 221. Find the three integers.
Sonja [21]

Answer:

Step-by-step explanation:

Square Root of 225 is 15 (with -15 also it would work but let’s stick to positive root)

Now, the 1st Odd Number is 15 -2 = 13 and the 3rd Odd Number is 15 + 2 = 17.

The required Numbers are 13 and 17.

This works for 3 consecutive Even Numbers also.

Why does it work?

Because, if we have 3 numbers to be a-2, a and a+2 (Doesn’t really matter if a is positive or negative)

(a-2)*(a+2) = a^2 - 4

So, you see adding 4 to the Product of the 1st Number and the 3rd Number (a^2 - 4 + 4 = a^2) gives you the square of the Middle Number, which is a^2!

7 0
3 years ago
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