Is -4x + y = -9 parallel to x + 4y = 12
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Given:
Total number of students = 10
To find:
How many was can you award first, second, and third place?
Solution:
Total number of students is 10. So, the total possible ways for the first award is 10.
We know that one student can hold only one place. So, after giving the first award, the number of remaining students is 9 and the total possible ways for the second award is 9.
Similarly, the total possible ways for the third award is 8.
Now, the total number of ways to award first, second, and third place is:
Therefore, the total number of ways to award first, second, and third place is 720.