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neonofarm [45]
3 years ago
10

Find the X & Y value

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

Step-by-step explanation:

x = 72°

y = 61°

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An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let A_i\,,\,B_i\,,\,C_i denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

If A lost and B wins: P\left ( B_1|A_1^{c} \right )=\frac{4}{11}

If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
3 years ago
A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

3 0
3 years ago
According to the U.S. Bureau of the Census in its Current Population Reports (Series P60) the average
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:

5, 7, 9, 10, 10, 11, 12

10 is the number in the middle. Therefore the median is 10
7 0
4 years ago
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A 7th grade teacher at a local middle school wants to know which
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The answer is Option C) 7th graders in her school.

In order to ascertain the suitability of a candidate for any popular position, his popularity can be assessed by taking a survey of the concerned sample.

7 0
2 years ago
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