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2 years ago

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The hypotenuse of a triangle is 30 cm long and the length of leg A is 15 cm. How long is leg B? (round the the nearest tenth) PL

EASE ILL GIVE BRAINLIST ILL GIVE BRAINLIST THIS IS VERY URGENT NOWWWWWW

1 answer:

makvit [3.9K]2 years ago

3 0

Answer:about 26

Step-by-step explanation:

30^2-15^2

Square root it 25.98 about 26

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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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11 months ago

Read 2 more answers

Can anyone help me in this whole math question? Especially Number b and c. <br>Thanks.

Bogdan [553]

Answer:

Irregular polygons are polygons that do not have equal sides or equal angles. When finding the area of an irregular polygon, partition the polygon into smaller regular polygon shapes. You can then plug those measurements into their respective area formulas and multiply to find the area of one part of the shape.

This is 16cm.

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2 years ago

I’m confused?????????

QveST [7]

Answer:

The equation of the line is y - 3 = 2.5(x - 2) ⇒ D

Step-by-step explanation:

The rule of the slope of a line is m = $\frac{y2-y1}{x2-x1}$ , where

(x1, y1) and (x2, y2) are two points on the line

The point-slope form of a line is y - y1 = m(x - x1), where

(x1, y1) is a point on the line

From the given figure

∵ The line passes through points (2, 3) and (0, -2)

∴ x1 = 2 and y1 = 3

∴ x2 = 0 and y2 = -2

→ Substitute them in the rule of the slope to find it

∵ m = $\frac{-2-3}{0-2}=\frac{-5}{-2}=2.5$

∴ m = 2.5

→ Substitute the values of m, x1, y1 in the form of the equation above

∵ m = 2.5, x1 = 2, y1 = 3

∵ y - 3 = 2.5(x - 2)

∴ The equation of the line is y - 3 = 2.5(x - 2)

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2 years ago

Find the solutions to the equation by completing the square. x2-6x=7

lianna [129]

Subtract 7 from both sides

x^2 - 6x - 7 = 7 - 7

Simplify

x^2 - 6x - 7 = 0

Answer :

The final solutions to the quadratic equation are:

x = 7, -1

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2 years ago

Please help me this is urgent! Both need an answer.

dolphi86 [110]

My answer is B and A that's my answer

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3 years ago