A group of six golfers paid $295 to play a round of golf. Of the golfers, one is a member of the club and five are nonmembers. A
1 answer:
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Answer:
Explained below.
Step-by-step explanation:
The complete question is:
Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.
What is P(A and B)?
What is P(A | B)?
Is P(A | B) equal to P(A)?
Are events A and B dependent or independent?
A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?
What general conclusion would you make about mutually exclusive and independent events given the results of this problem?
Solution:
The probability of the two events <em>A</em> and <em>B</em> are:
P(A) = 0.30 and P(B) =0.40
(a)
Compute the value of P (A ∩ B) as follows:
This is because mutually exclusive events are those events that cannot occur together.
(b)
Compute the value of P (A | B) as follows:
Thus, the value of P (A | B) is 0.
(c)
No, P (A | B) is not equal to the P (A).
(d)
As mentioned in part (a), mutually exclusive events are those events which cannot occur together.
That is, .
Events A and B are independent if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.
That is, .
The concepts of mutually exclusive events and independent events are not the same.
(e)
As the it is provided that A and B are mutually exclusive events, we know that .
Now compute the value of as follows:
Thus, the events A and B are not independent.
Thus, if two events are mutually exclusive events they cannot be independent.
Answer:
\frac{1}{230230}
Step-by-step explanation:
Given that in a certain lottery, an urn contains balls numbered 1 to 26
From this urn, 6 balls are chosen randomly, without replacement.
Bet amount 1 dollar and he selects a set of six numbers.
If these match with those chosen from the urn he wins (order does not matter)
Total ways of choosing 6 out of 26 =
The way he selects = 1
Hence probability of winning =
with one ticket