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inessss [21]
3 years ago
11

A group of six golfers paid $295 to play a round of golf. Of the golfers, one is a member of the club and five are nonmembers. A

nother group of golfers consists of two members and three nonmembers. They paid a total of $205.
What is the cost for a member to play a round of golf, and what is the cost for a
nonmember?

Help pls
Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Bred Sheeran

Vladimir Gluten

Toast Malone

Elon Crust

Mr Yeast

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A milloniare estimates her wealth to be $2.2×10 to the nearst million dollars.what are the lower and upper bounds for the millio
Andrews [41]

Answer:

2.2 x10= = 22.2 =22 million.

Step-by-step explanation:

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4 years ago
The length of a rectangle is one unit shorter than one-sixth of the width x which expression represents the perimeter of the rec
wlad13 [49]
Hi,

L = (1/6)x - 1

P = 2x + 2L = 2x + (2/6)x - 2

P= (7/3)x - 2

x being the width.


Hope this helps!
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How to construct a right scalene triangle using no given lengths with a ruler and a compass
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A scalene triangle contains three unequal in length sides. Therefore, a right scalene triangle can be constructed without the use of a ruler or compass. The 90-degree angle can be signified by a small box in the corner of the triangle that measures 90 degrees.
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3 years ago
Can anyone pls help me with this I'll mark as brainlist for correct answer please do explain in detail each answers Ty! (I'm pre
densk [106]

<u>Question 8</u>

a^2 + 7a + 12

= (a+3)(a+4)

When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).

An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.

a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)

= (-7 +or- sqrt(1))/2

= -3 or -4

These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).

<u>Question 10</u>

-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18

Rewrite each fraction with a common denominator so you can combine the fractions into one.

= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18

= (-6(x - y) + 9(4x - 7y) - (x + y)) /18

Expand the brackets and collect like terms.

= (-6x + 6y + 36x - 63y - x - y)/18

= (29x - 58y)/18

= 29/18 x - 29/9 y

7 0
2 years ago
Here is a triangle with the height on the side of the triangle. Use the formula: (1/2)*(Base)*(Height) to find the area of the t
jasenka [17]

<em>(If one square on the graph = one centimeter)</em>

<u>b = 10cm</u>

<u>b = 10cmh = 10cm</u>

Area:

=  \frac{1}{2}  \times b \times \: h

=  \frac{1}{2 }  \times 10 \times 10

=  \frac{1}{2}  \times 100

= 50 {cm}^{2}

3 0
3 years ago
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