k, n - integers
2k+1 - an odd integer
2n+1 - another odd integer
The product of them:
(2k + 1)(2n + 1) =
= 4kn + 2k + 2n + 1 =
= 2(2kn + k + n) + 1
The product of integers (2kn) is integer
and the sum of them (2kn+k+n) also is integer
So (2k + 1)(2n + 1) = 2(2kn + k + n) + 1 is an odd integer
The answer is 12/13 in fraction form or 92% as a percent
Answer:
880 times 0.45 equals 396 as his/her commissioner fee
Step-by-step explanation:
Answer:
Step-by-step explanation:
What are the choices?