Answer:
31 miles
Step-by-step explanation:
If you multiply 0.62 by 50 you will get 31.
Please keep in mind that I am human and make mistakes. This answer could be wrong but this is my opinion on what the answer is.
Answer:
9 inches
Step-by-step explanation:
Do the question algebraically, represented by this equation:
let x be the shorter piece
x + (x + 8) = 26 (longer piece is 8 units longer)
Remove brackets
x + x + 8 = 26 Combine like terms
2x + 8 = 26 Start isolating "x"
2x + 8 - 8 = 26 - 8 Subtract 8 from both sides
2x = 18
2x/2 = 18/2 Divide both sides by 2
x = 9 shorter piece
The shorter piece would be 9 inches.
If you needed the longer piece too:
longer piece = x + 8
x + 8
= 9 + 8
= 17
The longer piece would be 17 inches.
Check your answer:
Longer + Shorter = 26 Substitute the lengths
17 + 9 = 26 Add
26 = 26 same number
LS = RS left side equals right side
The answer is correct.
Answer:
the total cost for 4 1/5 yds of fabric would be $33.39.
Step-by-step explanation:
To answer this, multiply the quantity purchased (4.2 yd) by the unit cost ($7.95/yd):
(4.2 yd)($7.95/yd) = $33.39
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➷ final = original x multiplier^n
n is the number of years
Substitute the values in:
final = 3800 x 1.054^3
final = 4449.440763
The closest answer is A
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Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71