<span>7 no encaja en 4, por lo que la respuesta sería cero 7 ajustes en 4, cero veces</span>
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer: 3/2
Step-by-step explanation:
<u>Given</u>
6/10 + 9/10
<u>Add the numerator together</u>
= (6 + 9) / 10
<u>Simplify by addition</u>
= 15 / 10
<u>Simplify to simplest form by division</u>
= (15 ÷ 5) / (10 ÷ 5)
= 3 / 2
Hope this helps!! :)
Please let me know if you have any questions
