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Scilla [17]
3 years ago
10

How do I solve this

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Step-by-step explanation:

\bf \underline{Solution-} \\

\textsf{Given,}\\

\sf{ \frac{ {a}^{6} {b}^{4}  }{ {a}^{2} {b}^{3}  } } \\

\textsf{Using law of intergal expo.. aᵐ ÷ aⁿ = aᵐ - ⁿ}\\

\sf{ \Rightarrow \:  {a}^{(6 - 2)}  {b}^{(4 - 3)} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{1} } \\

\sf{ \Rightarrow \:  {a}^{4}  {b}^{} } \\

\bf \underline{Hope\: this\: helps.} \\

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Pie

Answer:

The correct answer is 1,51%

Step-by-step explanation:

To get the probability  equally likely of the first 6 examined that have a defective compressor, we use the following formula

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As there are multiple events ,  and all must be achieve, we multiply the probabilities.

P1=7 / 11

P2=6 / 10

P3=5 / 9

P4=4 / 8

P5=3 / 7

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P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515

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D

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  see below

Step-by-step explanation:

In addition to the exponent rule ...

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  1. 125^3 = (5^3)^3 = 5^(3·3) = 5^9
  2. 81^7 = (9^2)^7 = 9^(2·7) = 9^14
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  4. (1/64)^3 = ((1/2)^6)^3 = (1/2)^(6·3) = (1/2)^18
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3 years ago
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