All categories

2 years ago

How do I solve this

Mathematics

1 answer:

Sladkaya [172]2 years ago

4 0

Step-by-step explanation:

$\bf \underline{Solution-} \\$

$\textsf{Given,}\\$

$\sf{ \frac{ {a}^{6} {b}^{4} }{ {a}^{2} {b}^{3} } } \\$

$\textsf{Using law of intergal expo.. aᵐ ÷ aⁿ = aᵐ - ⁿ}\\$

$\sf{ \Rightarrow \: {a}^{(6 - 2)} {b}^{(4 - 3)} } \\$

$\sf{ \Rightarrow \: {a}^{4} {b}^{1} } \\$

$\sf{ \Rightarrow \: {a}^{4} {b}^{} } \\$

$\bf \underline{Hope\: this\: helps.} \\$

You might be interested in

A hot-air balloon is 160 ftabove the ground when a motorcycle (traveling in a straight line on a horizontal road) passes dire

Charra [1.4K]

Answer:

73.77 ft/s

Step-by-step explanation:

Let's imagine this situation as a right triangle where the distance between the two points is the hypotenuse.

-Applying Pythagoras theorem:

$z^2=x^2+y^2\\\\z=\sqrt{x^2+y^2}\\\\x=dx*t+x_i, x_i=0\\\\y=dy*t+y_i\\\\y_i=160\ ft$

#Take the derivative of the first equation and solve for $dz$ :

$d(z^2=x^2+y^2)\\\\2z*dz=2x*dx+2y*dy\\\\dz=\frac{x*dx+y*dy}{z}\\\\dz=\frac{x*dx+y*dy}{\sqrt{x^2+y^2}}\\\\\\dz=\frac{dx^2*t+dy(dy*t+160)}{\sqrt{(dx*t)^2+(dy*t)}}$

#We then substitute the values given in the question to solve for $dz$ :

$dz=\frac{7*66^2+14(14*7+160)}{\sqrt{(66*7)^2+7*14+160}}\\\\=73.78$

Hence, the rate of change of the distance between the motorcycle and the balloon 7 seconds later is 73.77 ft/s

3 0

3 years ago

What is -8 divide 0?

GenaCL600 [577]

Answer:

You can't do that. There is no answer

6 0

3 years ago

Read 2 more answers

9. Si Diana compro una botella de aguardente, una de vino y una de wisky, todas por $260.000 botella de wisky costo el doble que

VLD [36.1K]

The answer is D.32.000

7 0

3 years ago

Please help me! And please no scam answers

Yuri [45]

Answer:

Average rate of change: $-3$

Step-by-step explanation:

Remember:

The average rate of change of a function over an interval $[a,b]$ is $\frac{f(b)-f(a)}{b-a}$

Given:

$[a,b]=[1,7]$

$f(b)=f(7)$

$f(a)=f(1)$

Calculation:

$f(b)=f(7)=-(7)^2+5(7)+14=-49+35+14=-49+49=0$

$f(a)=f(1)=-(1)^2+5(1)+14=-1+5+14=4+14=18$

$\frac{f(b)-f(a)}{b-a}=\frac{0-18}{7-1}=\frac{-18}{6}=-3$

Therefore, the average rate of change of the function $g(x)=-x^2+5x+14$ over the interval $1\leq x\leq7$ is $-3$ .

6 0

2 years ago

what is the error? at 9am the temperature was -4 degress forienhieght by the noon the tempereture was -12 degress forienhight a

Cloud [144]

if it were getting warmer, the negative number would get closer to 0, not farther away.

For example, at 9am the temperature was -4 degrees and by noon it was -1 degrees. It has gotten 3 degrees warmer.

5 0

3 years ago