3 years ago

Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following.

1 answer:

8 0

4. Since f(x) = 2x - 1, we are looking for h(2x - 1), which is (2x-1)^2 + 1. By tha time you expand this you'll get, 4x^2 - 4x + 2. So that is the answer.
5. f(f(x)) = f(2x - 1) = 2(2x - 1) - 1 = 4x - 3
6. h(g(x)) = h(3x) = (3x)^2 + 1 = 9x^2 + 1

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