suppose that y=5x+1 and it is required that y be within 0.005 units of 7. for what values of x will this be true
1 answer:
Answer:
1.199 ≤ x ≤ 1.201
Step-by-step explanation:
You want ...
|y -7| ≤ 0.005
Substituting the expression for y, you have ...
|5x+1 -7| ≤ 0.005
|x -1.2| ≤ 0.001 . . . . . simplify, divide by 5
-0.0001 ≤ x -1.2 ≤ 0.001 . . . . . "unfold" the absolute value
1.199 ≤ x ≤ 1.201 . . . . . . . . . . . .add 1.2
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Answer:
scale factor = 3
Step-by-step explanation:
The scale factor is the ratio of corresponding sides, larger to smaller.
scale factor = 
= 
= 3
X + y = 4...x = 4 - y
2x + 3y = 0
2(4-y) + 3y = 0
8 - 2y + 3y = 0
-2y + 3y = 0 - 8
y = -8
x + y = 4
x - 8 = 4
x = 4 + 8
x = 12
solution is : (12,-8)
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