Question

suppose that y=5x+1 and it is required that y be within 0.005 units of 7. for what values of x will this be true

Answer 1

Answer:

  1.199 ≤ x ≤ 1.201

Step-by-step explanation:

You want ...

  |y -7| ≤ 0.005

Substituting the expression for y, you have ...

  |5x+1 -7| ≤ 0.005

  |x -1.2| ≤ 0.001 . . . . . simplify, divide by 5

  -0.0001 ≤ x -1.2 ≤ 0.001 . . . . . "unfold" the absolute value

  1.199 ≤ x ≤ 1.201 . . . . . . . . . . . .add 1.2