Alright
s=number of hours headd south
e=number of hours headed east
s+e=8
and
total is 147 miles
distance=speed times time
15s+24e=147
we got 2 equations
s+e=8
15s+24e=147
subsitution
s+e=8
minus e both sides
s=8-e
subsitut 8-e for s in other equaton
15s+24e=147
15(8-e)+24e=147
120-15e+24e=147
120+9e=147
minus 120 both sides
9e=27
divide both isdes by 9
e=3
sub back
s=8-e
s=8-3
s=5
it was headed south 5 miles
Answer:
2/5
Step-by-step explanation:
To find the slope of a line segment, find the difference in y and divide by the difference in x (delta y / delta x)
Delta y: -7 - (-13) = 6
Delta x: 15 - 0 = 15
Slope = delta y / delta x
Slope = 6/15 = 2/5
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Add all the sides together
7.2+14.8+16.1+18 = 56.1
Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:
20^2=12^2+x^2
400=144+x^2
x^2=400-144
x^2=256
x=16
