Answer:
d < 1
Step-by-step explanation:
First, we have to get d on the same side of the equation. So we will subtract d from both sides and the equation will be 12d-d < + 11. We could also write this problem as d(12-1) < 11, which when simplified would be d(11) < 11. Next, divide both sides by 11 and you get d< 1. Hope this helps and have a great day!!:D
This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.
<span>–4(x + 3) ≤ –2 – 2x
>>.....-4x -12 </span>≤ -2 -2x
>> -12 +2 ≤ +2x
>> - 10 ≤ 2x
>> -5 ≤ x............>> x >= -5
This answer is not represented in the pictures you attached
The line starts in x = -5 and goes up to infinity
The estimated cost is 400$
Answer:
Required rule for
is
.
Step-by-step explanation:
Given that,

From the question: we have to write the
term of Arithmetic sequence.
Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

where,
is the first term of A.P
is the common difference.
is the last term or general term.
The above sequence to be in A.P then their common difference should be equal.

Now, Formula of General Term is 
So, 
Substituting the value of
we get,

Then General term (
) of given data is

Therefore, Required rule for
is
.