Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Answer:
going from left to right: 200, 400, 800
Step-by-step explanation:
25 x 2 = 50
50 x 2 = 100
100 x 2 = 200
200 x 2 = 400
400 x 2 = 800
just follow the pattern
Answer:
The heat from the sun or heat released from the filament of a light bulb is the example of radiation.
Answer:
The diameter decreases at a rate of 0.053 cm/min.
Step-by-step explanation:
Surface area of an snowball
The surface area of an snowball has the following equation:
In which d is the diameter.
Implicit differentiation:
To solve this question, we differentiate the equation for the surface area implictly, in function of t. So
Surface area decreases at a rate of 3 cm2/min
This means that 
Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.
This is 
when 
. So
The diameter decreases at a rate of 0.053 cm/min.
Answer:
Step-by-step explanation:
Let the number is x.
<u>2/3 of a number is 10:</u>
<u>0.15 times of the number is:</u>
Correct choice is d
