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iren2701 [21]
2 years ago
8

Factorise plsany inappropriate answers will be reportedthanks xx

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
7 0
You have to figure out the highest common factor of each set of values:
9a + 21 = 3(3a + 7)
21b - 49 = 7(3b - 7)
54 - 6c = 6(9 - c)
8a + 32b = 8(a + 4b)
4p + 28q + 8r = 4(p + 7q +2r)
84a - 36b -12c = 6(14a - 6b - 2c)
6p + 9q + 15r = 3(2p + 3q + 5r)
18s - 30t + 54u = 6(3s - 5t + 9u)
Hope this helps :)
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How do you solve: 4/10y+28=0
Bezzdna [24]

Answer:

<h2>y = -70</h2>

Step-by-step explanation:

\dfrac{4}{10}y+28=0\qquad\text{subtract 28 from both sides}\\\\\dfrac{4:2}{10:2}y=-28\\\\\dfrac{2}{5}y=-28\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}y=-140\\\\2y=-140\qquad\text{divide both sides by 2}\\\\y=-70

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37.5% written as a decimal and as a fraction in simplest form
Angelina_Jolie [31]

p\%=\dfrac{p}{100}\\\\37.5\%=\dfrac{37.5}{100}=\dfrac{37.5\cdot10}{100\cdot10}=\dfrac{375}{1000}\\\\\dfrac{375}{1000}=\dfrac{375:125}{1000:125}=\dfrac{3}{8}\\\\\dfrac{375}{1000}=0.375\\\\Answer:\ \boxed{37.5\%=\dfrac{3}{8}=0.375}

7 0
3 years ago
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Use the scenario to answer the question. Tyrone was asked to write the recursive and explicit formula for the sequence {−4,−7,−1
Anton [14]

The last option: In his recursive formula, he should have the term an−1 instead of −4 to get an=an−1−3.

7 0
3 years ago
Factor 2x2+25x+50. Rewrite the trinomial with the x-term expanded, using the two factors.
zlopas [31]

9514 1404 393

Answer:

  • rewrite: 2x^2 +5x +20x +50
  • factored: (x +10)(2x +5)

Step-by-step explanation:

I find this approach the most straightforward of the various ways that trinomial factoring is explained or diagramed.

You want two factors of "ac" that have a total of "b". Here, that means you want factors of 2·50 = 100 that have a total of 25. It is helpful to know your times tables.

  100 = 1·100 = 2·50 = 4·25 = 5·20 = 10·10

The sums of these factor pairs are 101, 52, 29, 25, and 20. We want the pair with a sum of 25, so that's 5 and 20.

The trinomial can be rewritten using these factors as ...

  2x^2 +5x +20x +50

Then it can be factored by grouping consecutive pairs:

  (2x^2 +5x) +(20x +50) = x(2x +5) +10(2x +5) = (x +10)(2x +5)

_____

<em>Additional comment</em>

It doesn't matter which of the factors of the pair you write first. If our rewrite were ...

  2x^2 +20x +5x +50

Then the grouping and factoring would be (2x^2 +20x) +(5x +50)

  = 2x(x +10) +5(x +10) = (2x +5)(x +10) . . . . . same factoring

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2 years ago
I just need the answer please dont explain ​
zavuch27 [327]
Use photomath it’s faster and you get correct Answers!<3 have a good day
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