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Vinil7 [7]
3 years ago
7

8. What is the solution to the equation 3x + 5(4x-6)-8= 3x - 14? a. x = 1 b. r = 1.7 d. There are no solutions to this equation.

​
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

3x+5(4x-6)-8=3x-14

Step-by-step explanation:

Cancel out the terms on both sides of the equation. (3x)

5(4x-6)-8=-14

Distribute 5 through the parentheses.

20x-30-8=-14

Calculate the difference.

20x-38=-14

Move the constant to the right-hand side and change its sign.

20x=-14+28

Calculate the sum.

20x=24

Divide both sides of the equation by 20.

x=6/5, 1.2, or 1 1/5

Answer:

x=6/5, 1.2, or 1 1/5

Hope this helps! :)

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What is 513 + _ + 130 = 764? what is the missing number and can u pls do a explantation
dmitriy555 [2]

Answer:

121

Step-by-step explanation:

The missing number is 121. I got this by doing 764-130-513=121. You would do this because you are trying to find the number that would allow 130 and 513 to add up to 764.

Another way to look at this problem is 513+130= 643

764-643=121

In conclusion, 513+121+130=764

4 0
3 years ago
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Which of the following best describes the relationship between (x-3) and the polynomial x^3+4x^2+2?
Anna71 [15]
This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor
7 0
3 years ago
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Find two solutions to the equation (x^3 − 64)(x^5 − 1) = 0.
Rashid [163]

Answer:

the two roots are x = 1 and x = 4

Step-by-step explanation:

Data provided in the question:

(x³ − 64) (x⁵ − 1) = 0.

Now,

for the above relation to be true the  following condition must be followed:

Either  (x³ − 64) = 0 ............(1)

or

(x⁵ − 1) = 0 ..........(2)

Therefore,

considering the first equation, we have

(x³ − 64) = 0

adding 64 both sides, we get

x³ − 64 + 64 = 0 + 64

or

x³ = 64

taking the cube root both the sides, we have

∛x³ = ∛64

or

x = ∛(4 × 4 × 4)

or

x = 4

similarly considering the equation (2) , we have

(x⁵ − 1) = 0

adding the number 1 both the sides, we get

x⁵ − 1 + 1 = 0 + 1

or

x⁵ = 1

taking the fifth root both the sides, we get

\sqrt[5]{x^5}=\sqrt[5]{1}

also,

1 can be written as 1⁵

therefore,

\sqrt[5]{x^5}=\sqrt[5]{1^5}

or

x = 1

Hence,

the two roots are x = 1 and x = 4

4 0
3 years ago
Urgent: Find value of X
Gelneren [198K]
X= 26




The equation is setup like 2x+10=62 because the angles are the same
4 0
3 years ago
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Please help fast very urgent
Ira Lisetskai [31]

Answer: C 1 - 5i

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1 is real part graphed sideways

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And is graphed up and down

6 0
2 years ago
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