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Lena [83]
3 years ago
5

Solve the system using elimination. 2x-3y=16 x+y=24

Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

y=8 x=16

Step-by-step explanation:

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What's 9+10? Will give brainliest to whoever answers correctly.
Radda [10]

Answer:

9+10=19

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7 0
3 years ago
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The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter
CaHeK987 [17]
X - a leg  (x > 6);
x - 6 - a leg;
x + 1 - a <span>hypotenuse;</span>
Use the Pythagorean theorem
(x+1)^2=x^2+(x-6)^2

Use:(a\pm b)^2=a^2\pm2ab+b^2

x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}

x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}

The perimeter:

7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}
5 0
3 years ago
George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
Help here please. thank you
NISA [10]

Answer: A=C+7

Step-by-step explanation:

Let’s say hypothetically C=6, then B would be 4 since you would have to subtract 2 and A would be 13 since 4+9=13

The difference between 13 and 6 is 7, but that would work with any number and i’m just using c=6 as an example to make the problem easier to understand

4 0
2 years ago
Combine like terms please help 19m+23n+m-3n
Lera25 [3.4K]
19m+23n+m-3n=(19m+m)+(23n-3n)\\\\=\boxed{20m+20n}
7 0
3 years ago
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