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3 years ago

Which statements are true regarding the the price of the arrangements select three answers.

Mathematics

1 answer:

natulia [17]3 years ago

5 0

Answer:

The first three statements are correct, the other two are wrong

Second to last problem: WRONG - Since the second to last problem is marked down by 40% we subtract 40% from 100% to get 60%. Now we just do 0.60*28 = 16.8 which makes the statement wrong.

Last problem: WRONG - The last one is marked down by 50% so that is 100% - 50% to get 50%. We do 0.50 * 28 to get 14, making the statement wrong.

The first 3 statements are correct, and the 2 last ones are wrong

- Hope this helped! :)

Brainiest is most appreciated:)

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In the figure angle 2 and angle 3 are

anygoal [31]

I believe it’s c) complementary

6 0

2 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

I NEED HELP!!! 0+0 PLEASE HELP!! 50 pts

Burka [1]

Answer:

I think the answer is 0

Step-by-step explanation:

7 0

2 years ago

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Simplify 8(xy + 8) + 1.

kobusy [5.1K]

Look at the picture.

I hope this helps!

5 0

3 years ago

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Brainliest Please do one of the above (I would appreciate if you did more then one)

Temka [501]

Answer:

a) 52.5 ft. b)40.1ft c)12.5ft d) 72.6

Step-by-step explanation:

a) The height of the lighthouse is 84ft, and the angle of elevation is 58 degrees.

tan58=84/x

find x by dividing 84 by tan58, and you get 52.5ft.

b) do the same thing, except 131 is in the base of the right triangle shape. That being said, do tan17=x/131.

multiply 131 by tan17, and you get x=40.1 feet.

c) This question wants you to find the length of the slide, (basically the hypotenuse).

given the angle to be 46, do sin46=9/x

since sin is opp/hyp

9/sin46= 12.5ft

d) Find the angle of elevation by using inverse tan given the base to be 5, and the height to be 16ft.

tan^-1=(16/5)=theta

x=72.6 hope this helps!

5 0

2 years ago

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